Sun 09-Feb-14 09:32 PM | edited Sun 09-Feb-14 09:37 PM by Jamed600
I have a new Nikon 80-400 lens and want to play with it but we are having a harsh winter in Chicago so I have been experimenting indoors. I have never had a lens this big and am experimenting with handhold technique. As a baseline I set up the lens on a tripod and shot a ceiling fan/light wall switch plate (lots of crisp, little numbers- good for pixel peeping) about 20 feet away. I then handhold trying different things to see how close I can come to the clarity of the tripod mounted shot (I've got a ways to go but am seeing improvement). At one point I mounted my D600 on the lens (which was mounted on the tripod) and took a shot. The tripod position and lens settings were unchanged. Camera settings were the same and both shots in RAW. When I look at the two images in View NX2 the image of the switch plate is larger with the D800. On the vertical the plate fills the frame. In the D600 shot the plate is an inch short of filling the frame. So, it appears that there is greater magnification with the D800 but I don't understand why this would be the case. Both sensors are 36X24 and I assume the raw, uncropped image as it appears in NX2 is a function of sensor size. I know JPEG print size is larger with the D800 but I assume this due to pixel density and prints based on 300 PPI. Could it be that the 'film' planes of the two cameras are at different distances from the lens mounting yielding different fields of view? This is just academic curiosity but thought I might learn something by posing the question. Thanks for reading.
Sun 09-Feb-14 09:04 PM | edited Sun 09-Feb-14 09:07 PM by aolander
The field of view (with the same focal length lens) and the film plane distance are identical between the two cameras. Do you have the D800 set on one of the reduced image area size modes, e.g. DX, 1.2x?
Every slr or dslr that has ever been made that takes the standard Nikon F mount lens has the same mount to sensor/film distance. What you are seeing is the increased image size of the higher density sensor for equal magnifications. A 25% enlargement of the 36mp D800 will be larger than the 25% enlargement of the 24mp D600.
Sun 09-Feb-14 11:08 PM | edited Sun 09-Feb-14 11:14 PM by Leonard62
Every photo is enlarged by default. When I first open a raw file on my 27" monitor the default enlargement is 25%. The 25% enlargement of a D800 file is 17" wide where a 25% enlargement of a D3X (same as a D600) file the width is 14".
That's the only thing that will make a D800 file larger than a D600 file if the settings in both cameras is the same.
edit: The smallest I can view a 24mp file on my monitor with CNX2 is a 1% enlargement and in that case the photo is only 1/2" wide.
Len, thanks. I was in fact enlarging the image- to 100% in NX2 so that would magnify the difference. I know you must be right, it's just hard for me to get my head around. I think of the sensor dimensions (both 36X24) and think any equal magnification of both would give equal size. So the size difference on screen is the same principle as the JPEG print size e.g. 20"X13" for the D600 v 24.5"X16.4" for the D800. Thanks again, good learning exercise.